1. $\mathrm{CH}_3 \mathrm{OH} \quad \mathrm{HCO}_2 \mathrm{H}$
  2. $\mathrm{HCO}_2 \mathrm{H} \quad \mathrm{CH}_2 \mathrm{O}$
  3. $\mathrm{CH}_3 \mathrm{OH} \quad \mathrm{CH}_2 \mathrm{O}$
  4. $\mathrm{CH}_2 \mathrm{O} \quad \mathrm{CH}_3 \mathrm{OH}$

Solution

(i) $\mathrm{CH}_4+\mathrm{O}_2 \frac{\mathrm{Mo}_2 \mathrm{O}_3}{\Delta} \rightarrow \mathrm{HCHO}+\mathrm{H}_2 \mathrm{O}$ (ii) $2 \mathrm{CH}_4+\mathrm{O}_2 \stackrel{\mathrm{Cu} / 523 \mathrm{~K} / 100 \mathrm{~atm}}{\longrightarrow} 2 \mathrm{CH}_3 \mathrm{OH}$ Above reactions (equation) show complete combustion of methane $\left(\mathrm{CH}_4\right)$ with oxygen $\left(\mathrm{O}_2\right)$.

Asked in: AP EAMCET 2018 (24 Apr Shift 1)

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