Arrange the C-H bods $^{\prime} x^{\prime},{ }^{\prime} y^{\prime}$ and $^{\prime} z^{\prime}$ in decreasing order of their bond dissociation energies homolysis
Arrange the C-H bods $^{\prime} x^{\prime},{ }^{\prime} y^{\prime}$ and $^{\prime} z^{\prime}$ in decreasing…
Arrange the C-H bods $^{\prime} x^{\prime},{ }^{\prime} y^{\prime}$ and $^{\prime} z^{\prime}$ in decreasing order of their bond dissociation energies homolysis
- $\mathrm{Y}>\mathbf{X}>\mathbf{Z}$
- $Z>\mathbf{X}>\mathbf{Y}$
- $\mathrm{Z}>\mathrm{Y}>\mathbf{X}$
- $\mathrm{Y}>\mathbf{Z}>\mathbf{X}$
Solution
so bond dissociation energy order is
$E_1>E_2>E_3 \quad \text { i. } e, \quad(z)>(x)>(y)$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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