Given in the figure are two blocks A and B of weight 20   N and 100   N , respectively. These are…

Given in the figure are two blocks $A$ and $B$ of weight $20 \mathrm{N}$ and $100 \mathrm{N}$, respectively. These are being pressed against a wall by a force $F$ and kept in equilibrium as shown. If the coefficient of friction between the blocks is $0.1$ and between block $B$ and the wall is $0.15$, the frictional force applied by the wall on block $B$ is:

1. $150 \mathrm{N}$
2. $100 \mathrm{N}$
3. $80 \mathrm{N}$
4. $120 \mathrm{N}$

Solution

For complete state equilibrium of the system. The state friction on the block $B$ by the wall will balance the total weight $120 \mathrm{N}$ of the system.

Asked in: JEE Main 2015 (04 Apr)

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