Length of a rectangle is $(x+3)$ and breadth is $(x-3)$. Its area is

Length of a rectangle is $(x+3)$ and breadth is $(x-3)$. Its area is
  1. $x^{2} - 9$
  2. $x^{2} + 9$
  3. $x^{2} - 6$
  4. $x^{2} - 6x + 9$

Solution

Area = $(x+3)(x-3) = x^{2} - 9$.

Asked in: IMO

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