Length of a rectangle exceeds its breadth by $2$ m. Area is $48$ m$^{2}$. Length is

Length of a rectangle exceeds its breadth by $2$ m. Area is $48$ m$^{2}$. Length is
  1. $8$ m
  2. $6$ m
  3. $10$ m
  4. $12$ m

Solution

$L = B + 2$. $L \cdot B = 48 \Rightarrow (B+2)B = 48 \Rightarrow B^{2} + 2B - 48 = 0 \Rightarrow B = 6$ (positive root). $L = 8$.

Asked in: MH-SSC-9

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