Least thermally stable is $-$
- $\mathrm{CCl}_{4}$
- $\mathrm{SiCl}_{4}$
- $\mathrm{GeCl}_{4}$
- $\mathrm{GeBr}_{4}$
Solution
same metal with different halides is in order
$\mathrm{of} \mathrm{MF}_{4}>\mathrm{MCl}_{4}>\mathrm{MBr}_{4}>\mathrm{MI}_{4}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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