\(K_p\) for the conversion of oxygen to ozone at \(400 \mathrm{~K}\) is \(1.0 \times 10^{-30}\), its…

\(K_p\) for the conversion of oxygen to ozone at \(400 \mathrm{~K}\) is \(1.0 \times 10^{-30}\), its standard Gibbs energy change in \(\mathrm{kJ} \mathrm{mol}^{-1}\) is approximately
  1. 229.8
  2. 114.9
  3. -229.8
  4. -114.9

Solution

Given, \(K_p\) for the conversion of oxygen to ozone at \(400 \mathrm{~K}\) is \(1.0 \times 10^{-30}\). \(\left(\Delta G^{\circ}\right)\) standard Gibbs energy change \(=\) ? \(\Delta G^{\circ}=-R T \ln K_p=2.303 R T \log _{10} K_p\) Here, \(R=8.314 \mathrm{~J} / \mathrm{mol}\) \(\begin{aligned} T & =400 \mathrm{~K} \\ \Delta G^{\circ} & =-R T \log K_p \\ & =-8.314 \times 400 \times 2.303 \times \log 10^{-30} \\ & =22976570 \mathrm{~J} \mathrm{~mol}^{-1} \\ & =229.765 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned}\)

Asked in: AP EAMCET 2019 (22 Apr Shift 1)

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