Isomerisation of gaseous cyclobutene to butadiene is a first order reaction. At $\mathrm{T}(\mathrm{K})$, the rate constant of the reaction is $3.3 imes 10^{-4} \mathrm{~s}^{-1}$. What is the time required (in min ) to complete $90 \%$ of this reaction at the same temperature? $(\log 2=0.3)$

Question

Isomerisation of gaseous cyclobutene to butadiene is a first order reaction. At $\mathrm{T}(\mathrm{K})$, the rate constant of the reaction is $3.3 	imes 10^{-4} \mathrm{~s}^{-1}$. What is the time required (in min ) to complete $90 \%$ of this reaction at the same temperature? $(\log 2=0.3)$

Aicharya · Accepted Answer

$\begin{aligned} & 	ext { } \mathrm{K}=3.3 	imes 10^{-4} \mathrm{~s}^{-1} \ & \mathrm{~K}=\frac{2.303}{\mathrm{t}} \log \frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}} \ & 	herefore \mathrm{k}=\frac{2.303}{\mathrm{t}} \log \frac{100}{10} \ & \mathrm{t}=\frac{2.303}{3.3 	imes 10^{-4}} 	imes 1 \quad[\log 10=1] \ & \mathrm{t}=\frac{2.303}{3.3} 	imes 10^4 \ & \mathrm{t}=0.70 	imes 10^4 	ext { second }\end{aligned}$ $\begin{aligned} & t=7000 \mathrm{~s} \ & \mathrm{t}=\frac{7000}{60}=116.6 \mathrm{~min}\end{aligned}$

Isomerisation of gaseous cyclobutene to butadiene is a first order reaction. At $\mathrm{T}(\mathrm{K})$,…

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