' $F$ ' is the force between the two identical charged particles placed at a distance ' $\mathrm{Y}$ ' from each other. If the distance between the charges is reduced to half the previous distance, then force between them becomes

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{F}=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{\mathrm{q}^2}{\mathrm{r}^2} \ & 	herefore \frac{\mathrm{F}_2}{\mathrm{~F}_1}=\left(\frac{\mathrm{r}_1}{\mathrm{r}_2}ight)^2=(2)^2=4 \ & 	herefore \mathrm{F}_2=4 \mathrm{~F}_1 \end{aligned}$ .

' $F$ ' is the force between the two identical charged particles placed at a distance ' $\mathrm{Y}$ ' from…

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