$A B C$ is an equilateral triangle with $O$ as its centre. $\mathrm{F}_1, \mathrm{~F}_2$ and $\mathrm{F}_3$…

$A B C$ is an equilateral triangle with $O$ as its centre. $\mathrm{F}_1, \mathrm{~F}_2$ and $\mathrm{F}_3$ represent three forces acting along the sides $A B, B C$ and $A C$ respectively. If the total torque about $O$ is zero then the magnitude of $\mathrm{F}_3$ is
  1. $F_1+F_2$
  2. $F_1-F_2$
  3. $\frac{F_1+F_2}{2}$
  4. $2\left(F_1+F_2\right)$

Solution


Given: Net torque about O is \(=0\) \(\begin{aligned} & \left(\tau_1+\tau_2-\tau_3\right)=0 \\ & \Rightarrow\left(F_1+F_2-F_3\right) R=0 \\ & \therefore F_3=F_1+F_2 \end{aligned}\) .

Asked in: NEET 2012 (Screening)

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