$\mathrm{ABC}$ is an equilateral triangle. Charges $+\mathrm{q}$ are placed at each corner as shown in fig.…

$\mathrm{ABC}$ is an equilateral triangle. Charges $+\mathrm{q}$ are placed at each corner as shown in fig. The electric intensity at centre $O$ will be
  1. $\frac{1}{4 \pi \in_{0}} \frac{\mathrm{q}}{\mathrm{r}}$
  2. $\frac{1}{4 \pi \in_{0}} \frac{\mathrm{q}}{\mathrm{r}^{2}}$
  3. $\frac{1}{4 \pi \in_{0}} \frac{3 q}{r^{2}}$
  4. zero

Solution

Unit positive charge at $\mathrm{O}$ will be repelled equally by three charges at the three corners of triangle. By symmetry, resultant $\mathrm{E}$ at $\mathrm{O}$ would be zero. ^

Asked in: JEE Mains - Electrostatics - Test 2

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