$\mathrm{A} \rightarrow \mathrm{P}$ is a zero order reaction. At 298 K the rate constant of the reaction is…

$\mathrm{A} \rightarrow \mathrm{P}$ is a zero order reaction. At 298 K the rate constant of the reaction is $1 \times 10^{-3} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}$. Initial concentration of ' $A$ ' is $0.1 \mathrm{~mol} \mathrm{~L}^{-1}$. What is the concentration of ' $A$ ' after 10 sec ?
  1. $0.09 \mathrm{~mol} \mathrm{~L}^{-1}$
  2. $0.099 \mathrm{~mol} \mathrm{~L}^{-1}$
  3. $0.087 \mathrm{~mol} \mathrm{~L}^{-1}$
  4. $0.011 \mathrm{~mol} \mathrm{~L}^{-1}$

Solution

Given, $\begin{aligned} & \mathrm{K}=10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1} \\ & {\left[\mathrm{~A}_{\mathrm{o}}\right]=0.1 \mathrm{~mol} \mathrm{~L}^{-1}} \\ & \mathrm{t}=10 \mathrm{~s} \end{aligned}$ for zero order, $\begin{aligned} & {\left[\mathrm{A}_{+}\right]=\left[\mathrm{A}_0\right]-\mathrm{kt}} \\ & {\left[\mathrm{~A}_{+}\right]=0.1-10^{-3} \times 10} \\ & =0.1-10^{-2} \\ & =0.09 \mathrm{~mol} \mathrm{~L}^{-1} \end{aligned}$

Asked in: AP EAMCET 2024 (21 May Shift 2)

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