$A B$ is a vertical pole with $B$ at the ground level and $A$ at the top. $A$ man finds that the angle of elevation of the point $A$ from a certain point $C$ on the ground is $60^{\circ}$. He moves away from the pole along the line $B C$ to a point $D$ such that $C D=7 \mathrm{~m}$. From $D$ the…

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$A B$ is a vertical pole with $B$ at the ground level and $A$ at the top. $A$ man finds that the angle of elevation of the point $A$ from a certain point $C$ on the ground is $60^{\circ}$. He moves away from the pole along the line $B C$ to a point $D$ such that $C D=7 \mathrm{~m}$. From $D$ the angle of elevation of the point $A$ is $45^{\circ}$. Then the height of the pole is

Aicharya · Accepted Answer

$ \begin{aligned} & \mathrm{BD}=\mathrm{AB}=7+x \\ & \text { Also } \mathrm{AB}=\mathrm{x} \tan 60^{\circ}=x \sqrt{3} \\ & \therefore x \sqrt{3}=7+x \\ & \mathrm{x}=\frac{7}{\sqrt{3}-1} \\ & \mathrm{AB}=\frac{7 \sqrt{3}}{2}(\sqrt{3}+1) \end{aligned} $

$A B$ is a vertical pole with $B$ at the ground level and $A$ at the top. $A$ man finds that the angle of…

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