$\mathrm{A}(3,-4)$ is a vertex of $\triangle \mathrm{ABC}$ and $3 x+4 y-18=0$ is the perpendicular bisector…

$\mathrm{A}(3,-4)$ is a vertex of $\triangle \mathrm{ABC}$ and $3 x+4 y-18=0$ is the perpendicular bisector of the side $\mathrm{AB}$. If $\mathrm{C}=(6,3)$ then the centroid of the triangle is
  1. $(6,1)$
  2. $(-6,1)$
  3. $(-6,-1)$
  4. $(6,-1)$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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