$\mathrm{NaOH}$ is a strong base. What will be $\mathrm{pH}$ of $5.0 imes 10^{-2} \mathrm{M} \mathrm{NaOH}$ solution ? $(\log 2=0.3)$

Question

$\mathrm{NaOH}$ is a strong base. What will be $\mathrm{pH}$ of $5.0 	imes 10^{-2} \mathrm{M} \mathrm{NaOH}$ solution ? $(\log 2=0.3)$

Aicharya · Accepted Answer

Given $\left[\mathrm{OH}^{-}ight]=5 	imes 10^{-2}$ $ \begin{aligned} & 	herefore \mathrm{pOH}=-\log 5 	imes 10^{-2} \ & \quad \quad=-\log 5+2 \log 10=1.30 \ & \because \mathrm{pH}+\mathrm{pOH}=14 \ & \because \mathrm{pH}=14-\mathrm{pOH} \ & \quad=14-1.30=12.70 \end{aligned} $

$\mathrm{NaOH}$ is a strong base. What will be $\mathrm{pH}$ of $5.0 \times 10^{-2} \mathrm{M}…

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