$A B C D$ is a parallelogram, with $A C, B D$ as diagonals, then $\mathbf{A C}-\mathbf{B D}$ is equal to

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Aicharya · Accepted Answer

In $	riangle A B C$ $\mathbf{A C}=\mathbf{A B}+\mathbf{B C}$ and in $	riangle A B D \mathbf{A D}=\mathbf{A B}+\mathbf{B D z}$ $\mathbf{B C}=\mathbf{A B}+\mathbf{B D}$ $(\because \mathbf{A D}=\mathbf{B C}) \ldots(\mathrm{ii})$ From Eqs. (i) and (ii) $\begin{aligned} & \mathbf{A C}=\mathbf{A B}+\mathbf{A B}+\mathbf{B D} \ & \mathbf{A C}=\mathbf{B D}=2 \mathbf{A B}\end{aligned}$

$A B C D$ is a parallelogram, with $A C, B D$ as diagonals, then $\mathbf{A C}-\mathbf{B D}$ is equal to

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