$\int_0^{10 \pi}|\sin x| d x$ is

$\int_0^{10 \pi}|\sin x| d x$ is
  1. 20
  2. 8
  3. 10
  4. 18

Solution

$\int_0^{10 \pi}|\sin x| d x=10\left[\int_0^{\pi / 2} \sin x d x+\int_{\pi / 2}^\pi \sin x d x\right]$ $=10 \times[\cos x]_0^{\pi / 2}+[\cos x]_{\pi / 2}^\pi ; \quad 10[1+1]=10 \times 2=20$

Asked in: JEE Main 2002

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