Ionization potential of hydrogen atom is $13.6 \mathrm{eV}$. Hydrogen atoms in the ground state are excited…
Ionization potential of hydrogen atom is $13.6 \mathrm{eV}$. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 \mathrm{eV}$. According to Bohr's theory, the spectral lines emitted by hydrogen will be:
one
two
three
four
Solution
According to question
$\begin{aligned}
& 12.1=13.6\left(\frac{1}{l^2}-\frac{1}{n^2}\right) \\
& \Rightarrow \quad n^2=\frac{13.6}{1.5}=9 \\
& \Rightarrow \quad n=3 \\
&
\end{aligned}$
Number of spectral lines emitted
$\begin{aligned}
& =\frac{n(n-1)}{2}=\frac{3 \times 2}{2} \\
& =3
\end{aligned}$