Ionic radius (in $Ã…$ ) of $\mathrm{As}^{3+}, \mathrm{Sb}^{3+}$ and $\mathrm{Bi}^{3+}$ follow the order

Ionic radius (in $Ã…$ ) of $\mathrm{As}^{3+}, \mathrm{Sb}^{3+}$ and $\mathrm{Bi}^{3+}$ follow the order
  1. $\mathrm{As}^{3+}>\mathrm{Sb}^{3+}>\mathrm{Bi}^{3+}$
  2. $\mathrm{Sb}^{3+}>\mathrm{Bi}^{3+}>\mathrm{As}^{3+}$
  3. $\mathrm{Bi}^{3+}>\mathrm{As}^{3+}>\mathrm{Sb}^{3+}$
  4. $\mathrm{Bi}^{3+}>\mathrm{Sb}^{3+}>\mathrm{As}^{3+}$

Solution

Ionic radius increases in a group from top to bottom i.e., it increases from $\mathrm{As}^{3+}$ to $\mathrm{Bi}^{3+}$.

Asked in: AP EAMCET 2001

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