Initially a gas of diatomic molecules is contained in a cylinder of volume V 1 at a pressure P 1 and…

Initially a gas of diatomic molecules is contained in a cylinder of volume V1 at a pressure P1 and temperature 250 K. Assuming that 25% of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas at temperature 2000 K, when contained in a volume 2V1 is given by P2. The ratio P2/P1 is -

Solution

  P1=P1
v1=v1
T1=250
n1=n0
n2=0.75n0+2×0.25n0=1.25no
v2=2V1
T2=2000
P1V1=n1RT1
P2V2=n2RT2
P1V1=n0R×250
P22V1=.25n0R(2000)
equation (1) /(2)
P12P2=2501.25×2000
P1P2=15
P2P1=5

Asked in: JEE Main 2020 (06 Sep Shift 1)

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