In Young's double slit experiment, with a source of light having wavelength $6300 Å$, the first maxima will…

In Young's double slit experiment, with a source of light having wavelength $6300 Å$, the first maxima will occur when the
  1. path difference is $9200 Å$
  2. phase difference is $\pi$ radian
  3. phase difference is $\frac{\pi}{2}$ radian
  4. path difference is $6300 Å$

Solution

For maxima, path difference $=\mathrm{n} \lambda$ For first maximum, $\mathrm{n}=1$ $\therefore$ Path difference, $\lambda=6300 Å$

Asked in: MHT CET 2021 (20 Sep Shift 1)

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