In Young's double slit experiment, the slits separated by $0.6 \mathrm{~mm}$ are illuminated with light of…

In Young's double slit experiment, the slits separated by $0.6 \mathrm{~mm}$ are illuminated with light of $6600 Å$. Interference pattern is obtained on a screen placed at $4 \mathrm{~m}$ from slits. The minimum distance from the central maximum at which the average intensity is $50 \%$ of the maximum value is
  1. $0.21 \mathrm{~mm}$
  2. $2.1 \mathrm{~mm}$
  3. $0.11 \mathrm{~mm}$
  4. $1.1 \mathrm{~mm}$

Solution

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Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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