In Young's double slit experiment the slits are horizontal. The intensity at a point ' $\mathrm{P}$ ' on the…

In Young's double slit experiment the slits are horizontal. The intensity at a point ' $\mathrm{P}$ ' on the screen shown in the figure is $\frac{\mathrm{I}_0}{4}$ where $\mathrm{I}_0$ is maximum intensity. If the distance between the two slits $S_1$ and $S_2$ is $2 \lambda$, then the value of ' $\theta$ ' is

1. $\cos ^{-1}\left(\frac{1}{6}\right)$
2. $\sin ^{-1}\left(\frac{1}{12}\right)$
3. $\tan ^{-1}\left(\frac{1}{6}\right)$
4. $\sin ^{-1}\left(\frac{3}{4}\right)$

Solution

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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