In Young's double slit experiment, the ratio of intensities at two points on a screen when waves from the two slits have a path difference of zero and $\frac{\lambda}{4}$ is $\left[\cos 0^{\circ}=\sin 90^{\circ}=1, \sin 0^{\circ}=\cos 90^{\circ}=0\right]$

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Aicharya · Accepted Answer

$I=4 I_{0} \cos ^{2} \frac{\phi}{2}$ $\phi=\frac{2 \pi}{\lambda} 	imes \frac{\lambda}{4}=\frac{\pi}{2}$ $\frac{\phi}{2}=\frac{\pi}{4}$ $\frac{1}{I_{0}}=4 \cos ^{2} \frac{\pi}{4}=\frac{4}{2}=2: 1$

In Young's double slit experiment, the ratio of intensities at two points on a screen when waves from the…

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