In young's double slit experiment, the $\mathrm{n}^{ ext {th }}$ maximum of wavelength $\lambda_1$ is at a distance of $y_1$ from the central maximum. When the wavelength of the source is changed to $\lambda_2,\left(\frac{\mathrm{n}}{3} ight)^{ ext {th }}$ maximum is at a distance of $y_2$ from…

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In young's double slit experiment, the $\mathrm{n}^{	ext {th }}$ maximum of wavelength $\lambda_1$ is at a distance of $y_1$ from the central maximum. When the wavelength of the source is changed to $\lambda_2,\left(\frac{\mathrm{n}}{3}ight)^{	ext {th }}$ maximum is at a distance of $y_2$ from its central maximum. The ratio $\frac{y_1}{y_2}$ is

Aicharya · Accepted Answer

$\mathrm{y}_{\mathrm{n}}=\frac{\mathrm{n} \lambda \mathrm{D}}{\mathrm{~d}}$
For $\mathrm{n}^{\text {th }}$ maximum $\mathrm{y}_1=\frac{\mathrm{n} \lambda_1 \mathrm{D}}{\mathrm{~d}}...(i)$ For $\left(\frac{\mathrm{n}}{3}\right)^{\mathrm{rd}}$ maximum $y_2=\frac{\frac{\mathrm{n}}{3} \lambda_2 \mathrm{D}}{\mathrm{~d}}...(ii)$ $\therefore \quad \frac{y_1}{y_2}=\frac{\frac{n \lambda_1 D}{d}}{\frac{\frac{n}{3} \lambda_2 D}{d}} \quad \ldots[\operatorname{From}(\mathrm{i})$ and (ii) $]$ $\therefore \quad \frac{\mathrm{y}_1}{\mathrm{y}_2}=\frac{3 \lambda_1}{\lambda_2}$

In young's double slit experiment, the $\mathrm{n}^{\text {th }}$ maximum of wavelength $\lambda_1$ is at a…

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