In Young's double slit experiment, the $10^{ ext {th }}$ maximum of wavelength ' $\lambda_1$ ' is at a distance of ' $\mathrm{Y}_1$ ' from the central maximum. When the wavelength of the source is changed to ' $\lambda_2$ ', $5^{ ext {th }}$ maximum is at a distance ' $Y_2$ ' from the central…

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In Young's double slit experiment, the $10^{	ext {th }}$ maximum of wavelength ' $\lambda_1$ ' is at a distance of ' $\mathrm{Y}_1$ ' from the central maximum. When the wavelength of the source is changed to ' $\lambda_2$ ', $5^{	ext {th }}$ maximum is at a distance ' $Y_2$ ' from the central maximum. The ratio $\frac{\mathrm{Y}_1}{\mathrm{Y}_2}$ is

Aicharya · Accepted Answer

$\begin{aligned} & Y_1=\frac{10 \lambda_1 D}{d}, Y_2=\frac{5 \lambda_2 D}{d} \ & 	herefore \frac{Y_1}{Y_2}=\frac{10 \lambda_1}{5 \lambda_2}=\frac{2 \lambda_1}{\lambda_2}\end{aligned}$

In Young's double slit experiment, the $10^{\text {th }}$ maximum of wavelength ' $\lambda_1$ ' is at a…

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