In Young's double slit experiment, the ' $\mathrm{n}^{ ext {th ' }}$ maximum of wavelength ' $\lambda_1$ ' is at a distance ' $y_1$ ' from the central maximum. When the wavelength of the source is changed to ' $\lambda_2$ ', $\left(\frac{\mathrm{n}}{2} ight)^{ ext {th }}$ maximum is at '…

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In Young's double slit experiment, the ' $\mathrm{n}^{	ext {th ' }}$ maximum of wavelength ' $\lambda_1$ ' is at a distance ' $y_1$ ' from the central maximum. When the wavelength of the source is changed to ' $\lambda_2$ ', $\left(\frac{\mathrm{n}}{2}ight)^{	ext {th }}$ maximum is at ' $\mathrm{y}_2$ ' from its central maximum. The ratio $\frac{\mathrm{y}_1}{\mathrm{y}_2}$ is

Aicharya · Accepted Answer

$\mathrm{y}_1=\mathrm{n} \beta_1=\frac{\mathrm{n} \lambda_1 \mathrm{D}}{\mathrm{d}}$ and $\mathrm{y}_2=\frac{\mathrm{n}}{2} \beta_2=\frac{\mathrm{n} \lambda_2 \mathrm{D}}{2 \mathrm{~d}}$ $	herefore \frac{\mathrm{y}_1}{\mathrm{y}_2}=\frac{2 \lambda_1}{\lambda_2}$

In Young's double slit experiment, the ' $\mathrm{n}^{\text {th ' }}$ maximum of wavelength ' $\lambda_1$ '…

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