In Young's double slit experiment of central fringe is $I_0$ and fringe width is $\beta$. If a point is at a…

In Young's double slit experiment of central fringe is $I_0$ and fringe width is $\beta$. If a point is at a distance $x$ from the central fringe, then the intensity at that point is
  1. $I_0 \cos ^2\left(\frac{\pi x}{\beta}\right)$
  2. $I_0 \cos ^2\left(\frac{x}{\beta}\right)$
  3. $\frac{I_0}{4} \cos ^2\left(\frac{\pi x}{\beta}\right)$
  4. $I_0 \cos ^2\left(\frac{\pi \beta}{x}\right)$

Solution

Intensity at distance $x$ from central maximum is given by $ I=4 I_0 \cos ^2 \frac{\phi}{2} $ where, $\phi=\frac{2 \pi d}{\lambda} \sin \theta$ Also, $\quad \beta=\frac{\lambda D}{d}$
Combining these, we get $ I=I_0 \cos ^2\left(\frac{\pi x}{\beta}\right) $

Asked in: AP EAMCET 2018 (23 Apr Shift 2)

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