In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of…

In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes:
  1. half
  2. four times
  3. one-fourth
  4. double

Solution

β=λDd

β'=λD'd'

D'=2D,d'=d2

β'=λ×2Dd2=4λDd

β'=4β

Fringe width becomes 4 times.

Asked in: NEET 2020 (Phase 1)

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