In which of the following sets of molecules, the central atoms of molecules have same hybridisation?
In which of the following sets of molecules, the central atoms of molecules have same hybridisation?
- $\mathrm{NH}_3, \mathrm{CIF}_3$
- $\mathrm{H}_2 \mathrm{O}, \mathrm{SO}_3$
- $\mathrm{SF}_4, \mathrm{CH}_4$
- $\mathrm{XeF}_6, \mathrm{IF}_7$
Solution
$\begin{array}{|c|c|c|c|c|c|c|}\hline \text{Molecule} & \begin{array}{c} \text{Bond} \\
\text{pair} \end{array} & \begin{array}{c} \text{Lone} \\
\text{pair} \end{array} & \begin{array}{c} \text{Steric} \\
\text{No.} \end{array} & \begin{array}{c} \text{Molecular} \\
\text{type} \end{array} & \text{Hybridisation} & \text{Shape} \\
\hline 1. ~\mathrm{NH}_3 & 3 & 1 & 4 & \mathrm{AB}_3 \mathrm{E} & \mathrm{sp}^3 &\text{ Trigonal pyramidal} \\
\hline 2. ~\mathrm{ClF}_3 & 3 & 2 & 5 & \mathrm{AB}_3 \mathrm{E}_2 & \mathrm{sp}^3 \mathrm{~d} & \text{T-shape} \\
\hline 3. ~\mathrm{H}_2 \mathrm{O} & 2 & 2 & 4 & \mathrm{AB}_2 \mathrm{E}_2 & \mathrm{sp}^3 & \text{Bent} \\
\hline 4. ~\mathrm{SO}_3 & 3 & 0 & 3 & \mathrm{AB}_3 & \mathrm{sp}^2 & \text{Trigonal planar} \\
\hline 5. ~\mathrm{SF}_4 & 4 & 1 & 5 & \mathrm{AB}_4 \mathrm{E} & \mathrm{sp}^3 \mathrm{~d} & \text{See-Saw} \\
\hline 6. ~\mathrm{CH}_4 & 4 & 0 & 4 & \mathrm{AB}_4 & \mathrm{sp}^3 & \text{Tetrahedral} \\
\hline 7. ~\mathrm{XeF}_6 & 6 & 1 & 7 & \mathrm{AB}_6 \mathrm{E} & \mathrm{sp}^3 \mathrm{~d}^3 & \text{Square bipyramidal} \\
\hline 8. ~\mathrm{IF}_7 & 7 & 0 & 7 & \mathrm{AB}_7 & \mathrm{sp}^3 \mathrm{~d}^3 & \text{Pentagonal Bipyramidal} \\
\hline\end{array}$
$\therefore \quad \mathrm{XeF}_6$ and $\mathrm{IF}_7$ hare same hybridisation.
Asked in: AP EAMCET 2024 (19 May Shift 2)
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