In which of the following, orbitals are correctly arranged in the increasing order of their energies?
In which of the following, orbitals are correctly arranged in the increasing order of their energies?
4 f $ < 5$ p $ < 5$ d $ < 6$ s
5 p $ < 4$ f $ < 6$ s $ < 5$ d
5 p $ < 6$ s $ < 4$ f $ < 5$ d
5 p $ < 5$ d $ < 4$ f $ < 6$ s
Solution
For multielectron atoms, the energy of the orbitals increases with an increase in their $(\mathrm{n}+l)$ value.
Thus, the order will be :-
$
5 \mathrm{p} < 6 \mathrm{~s} < 4 \mathrm{f} < 5 \mathrm{~d}
$