In triangle $ABC$, $\angle A = 50^{\circ}$, $\angle B = 70^{\circ}$. Exterior angle at $C$ is
In triangle $ABC$, $\angle A = 50^{\circ}$, $\angle B = 70^{\circ}$. Exterior angle at $C$ is
- $120^{\circ}$
- $60^{\circ}$
- $110^{\circ}$
- $130^{\circ}$
Solution
Exterior at $C$ = $\angle A + \angle B = 120^{\circ}$.
Asked in: MH-SSC-9
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