In trapezium $ABCD$ with $AB \parallel CD$, $\angle A + \angle D$ equals

In trapezium $ABCD$ with $AB \parallel CD$, $\angle A + \angle D$ equals
  1. $180^{\circ}$
  2. $90^{\circ}$
  3. $120^{\circ}$
  4. $360^{\circ}$

Solution

Co-interior angles between parallel sides.

Asked in: MH-SSC-9

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