In transistor amplifier, base-emitter junction is forward biased and collector emitter junction is reverse…

In transistor amplifier, base-emitter junction is forward biased and collector emitter junction is reverse biased. The current gain is
  1. $\frac{\Delta \mathrm{I}_{\mathrm{E}}}{\Delta \mathrm{I}_{\mathrm{B}}}$
  2. $\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{E}}}$
  3. $\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{C}}}$
  4. $\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}$

Solution

In transistor amplifier, base-emitter junction is forward biased and collector emitter junction is reverse biased. The current gain is (Del)lc/(Del)lb

Asked in: MHT CET 2020 (14 Oct Shift 2)

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