In thin layer chromatography, a substance moved by a distance of $4 \mathrm{~cm}$, where as the solvent…

In thin layer chromatography, a substance moved by a distance of $4 \mathrm{~cm}$, where as the solvent moved by a distance of $5 \mathrm{~cm}$. Then the value of retardation factor $\left(R_f\right)$ is
  1. $0.8$
  2. $1.0$
  3. $9.0$
  4. $1.25$

Solution

$R_f=\frac{\text { distance travelled by solute }}{\text { distance travelled by solvent }}$ $R_f=\frac{4}{5}=0.8$

Asked in: AP EAMCET 2021 (24 Aug Shift 2)

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