In the Young’s double slit experiment the intensity of light at a point on the screen where the path difference is λ is K , ( λ being the wave length of light used). The intensity at a point where the path difference is λ 4 , will be:

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Aicharya · Accepted Answer

I m a x = 4 I 0 = K at the other point, path difference = λ 4 So, phase difference ϕ = 2 π λ × λ 4 = π 2 I ' = I 0 + I 0 + 2 I 0 I 0 cos ⁡ π 2 I ' = 2 I 0 = K 2

In the Young’s double slit experiment the intensity of light at a point on the screen where the path…

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