In the study of transistor as an amplifier if $\alpha=\frac{I_C}{I_E}=0.98$ and $\beta=\frac{I_C}{I_B}=49$,…

In the study of transistor as an amplifier if $\alpha=\frac{I_C}{I_E}=0.98$ and $\beta=\frac{I_C}{I_B}=49$, where $I_C, I_B$ and $\mathrm{I}_{\mathrm{E}}$ are cóllector, base and emitter current respectively then $\left(\frac{1}{\alpha}-\frac{1}{\beta}\right)$ is equal to
  1. zero
  2. $\frac{1}{2}$
  3. $2$
  4. $1$

Solution

$\begin{aligned} \frac{1}{\alpha}-\frac{1}{\beta} & =\frac{1}{0.98}-\frac{1}{49} \\ & =1.204-0.204=1\end{aligned}$

Asked in: MHT CET 2023 (11 May Shift 2)

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