In the reaction, the intermediate(s) is (are)

Question

Aicharya · Accepted Answer

- $\mathrm{OH}$ and in aqueous in alkaline medium $-\overline{\mathrm{O}}$ are ortho and para directing. We expect the main intermediate products as mono ortho/para substituted product. Remember! if we consider (b), which could be there in small amount then we need to consider even (d) because $-\overline{\mathrm{O}}$ is strongest activating group that facilitates electrophilic substitution reaction overall on the ring. $-\overline{\mathrm{O}}$ activates ortho and para position more but doesn't deactivate the meta position. We get a small amount of even the meta substituted product. But, as the question appears to be directly concerned answer should be only (a) and (c). Reaction mechanism (Electrophilic substitution) Conceptual II

In the reaction, the intermediate(s) is (are)

Solution