In the reaction, $A$ is

In the reaction,
$A$ is

1. $\mathrm{HgSO}_4 / \mathrm{H}_2 \mathrm{SO}_4$
2. $\mathrm{Cu}_2 \mathrm{Cl}_2$
3. $\mathrm{H}_3 \mathrm{PO}_2$ and $\mathrm{H}_2 \mathrm{O}$
4. $\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}$

Solution

When diazonium salt is treated with $\mathrm{H}_3 \mathrm{PO}_2$ followed by hydrolysis, it diazonium group is replaced by $-\mathrm{H}$ resulting to the formation of hydrocarbon. Thus, $A$ must be $\mathrm{H}_3 \mathrm{PO}_2 / \mathrm{H}_2 \mathrm{O}$.

Asked in: NEET 2013 (All India)

Practice more Hydrocarbons questions on Aicharya