In the reaction $2 \mathrm{PCl}_{5} ightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$, the change…

In the reaction $2 \mathrm{PCl}_{5} ightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$, the change in hybridisation is from
  1. $s p^{3} d$ to $s p^{3}$ and $s p^{3} d^{2}$
  2. $s p^{3} d$ to $s p^{2}$ and $s p^{3}$
  3. $s p^{3} d$ to $s p^{3} d^{2}$ and $s p^{3} d^{3}$
  4. $s p^{3} d^{2}$ to $s p^{3}$ and $s p^{3} d$

Solution

$2 \mathrm{PCl}_{5} ightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$
$\uparrow s p^{3} d \quad \uparrow s p^{3} \uparrow s p^{3} d^{2}$ .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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