In the product F → = q ( v → × B → ) = q v → × B i ^ + B j ^ + B 0 k ^ For q = 1 and v → = 2 i ^ + 4 j ^ + 6…

In the product F=q(v×B) =qv×Bi^+Bj^+B0k^

For q=1 and v=2i^+4j^+6k^ and F=4i^-20j^+12k^

What will be the complete expression for B?

  1. -8ı^-8j^-6k^
  2. -6ı^-6j^-8k^
  3. 8i^+8j^-6k^
  4. 6i^+6j^-8k^

Solution

4ı^-20ȷ^+12k=(2ı^+4ȷ^+6k^)×Bı^+Bȷ^+Bok^

4ı^-20ȷ^+12k^=+ı^-ȷ^+k^246BBB0

=4B0-6Bı^-2B0-6Bȷ^+(2B-4B)k^

4B0-6B=4

2B0-6B=20

2B-4B=12B=6

So, 2B0-6(-6)=20

2B0=20-36B0=-8

B=-6ı^-6ȷ^-8k^

Asked in: NEET 2021

Practice more Magnetic Effects of Current questions on Aicharya