In the prime factorization of $37 !=2^{\alpha_2} \cdot 3^{\alpha_3} \cdot 5^{\alpha_5} \ldots 37^{\alpha_{37}}$ the ratio $\alpha_3: \alpha_5=$

Question

Aicharya · Accepted Answer

No solution. Refer to answer key.

In the prime factorization of $37 !=2^{\alpha_2} \cdot 3^{\alpha_3} \cdot 5^{\alpha_5} \ldots…