In the presence of an acid, the initial concentration of cane sugar was reduced from $0.20$ to $0.10 \mathrm{M}$ in 5 hours and from $0.2$ to $0.05 \mathrm{M}$ in 10 hours. The reaction is of :

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Aicharya · Accepted Answer

$\mathrm{k}_{1}=\frac{1}{5} \mathrm{In} \frac{0.2}{0.1} ; \mathrm{k}_{2}=\frac{1}{10} \operatorname{In} \frac{0.2}{0.05} ; \mathrm{k}_{1}=\mathrm{k}_{2}$ *

In the presence of an acid, the initial concentration of cane sugar was reduced from $0.20$ to $0.10…

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