$X$ and $Y$ can respectively be
In the Newman projection for 2,2-dimethylbutane $X$ and $Y$ can respectively be
$X$ and $Y$ can respectively be
- $\mathrm{H}$ and $\mathrm{H}$
- $\mathrm{H}$ and $\mathrm{C}_2 \mathrm{H}_5$
- $\mathrm{C}_2 \mathrm{H}_5$ and $\mathrm{H}$
- $\mathrm{CH}_3$ and $\mathrm{CH}_3$
Solution
Conformation projection along $\mathrm{C}_1-\mathrm{C}_2$ $\mathrm{C}_1$ contains all three $\mathrm{Hs}$ So, $\quad X=\mathrm{H}$
$\mathrm{C}_2$ contains two methyl and one ethyl group So, $\quad Y=\mathrm{C}_2 \mathrm{H}_5$ Conformational projection along $ \mathrm{C}_2-\mathrm{C}_3 $ $\mathrm{C}_2$ contains three methyl groups $\left(\mathrm{C}_2\right.$ form back carbon in the given structure) So, $\quad Y=\mathrm{CH}_3$
$\mathrm{C}_3$ contains two Hs and one methyl group $\left(\mathrm{C}_3\right.$ form front carbon in the given structure) So, $\quad X=\mathrm{CH}_3$ $\mathrm{C}_3$ contains two Hs and one methyl group $\left(\mathrm{C}_3\right.$ form front carbon in the given structure) So, $\quad X=\mathrm{CH}_3$ Isomerism (Stereochemistry) Conceptual (Structural visualisation) III
Asked in: JEE Advanced 2010 (Paper 1)
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