In the hydrocarbon The state of hybridisation of carbons 1,3 and 5 are in the following sequence

In the hydrocarbon The state of hybridisation of carbons 1,3 and 5 are in the following sequence

1. $s p^2, s p, s p^3$
2. $s p, s p^3, s p^2$
3. $s p, s p^2, s p^3$
4. $s p^3, s p^2, s p$

Solution

Hence, the state of hybridisation of carbons 1,3 and 5 are $s p, s p^3$ and $s p^2$ respectively.

Asked in: NEET 2008 (Screening)

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