In the ground state of $\mathrm{Cu}^{+}$, the number of shells occupied, subshells occupied, filled orbitals…
In the ground state of $\mathrm{Cu}^{+}$, the number of shells occupied, subshells occupied, filled orbitals and unpaired electrons respectively are
- $4,8,15,0$
- $3,6,15,1$
- $3,6,14,0$
- $4,7,14,2$
Solution
$\mathrm{Cu}^{+}=1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 3 d^{10}$.
Shells occupied $=3$, sub-shells occupied $=6$, filled orbitals $=14$. Unpaired $e^{-}=0$.
Asked in: NEET 2022 (Phase 2)
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