In the given reaction sequence, the major product ' C ' is : C 8 H 10 ⟶ HNO 3 H 2 SO 4 A…

In the given reaction sequence, the major product ' $C$ ' is :

$C_{8} H_{10} \underset{H_{2} {SO}_{4}}{\overset{{HNO}_{3}}{⟶}} A \underset{Δ}{\overset{{Br}_{2}}{⟶}} B \underset{KOH}{\overset{alcoholic}{⟶}} C$

Solution

In first step nitration of benzene ring will take place at para position, since ethyl group is ortho-para directing in nature.

Then halogenation reaction will take place at benzyl position followed by dehydrohalogenation reaction with alcoholic KOH.

Asked in: JEE Main 2022 (24 Jun Shift 1)

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