In the given P - V diagram, a monoatomic gas γ = 5 3 is first compressed adiabatically from state A…

In the given P-V diagram, a monoatomic gas γ=53 is first compressed adiabatically from state A state B. Then it expands isothermally from state B to state C. [Given : 130.6=0.5,ln20.7].

Which of the following statement(s) is(are) correct?

  1. The magnitude of the total work done in the process ABC is 144 kJ
  2. The magnitude of the work done in the process BC is 84kJ.
  3. The magnitude of the work done in the process AB is 60kJ.
  4. The magnitude of the work done in the process CA is zero.

Solution

For adiabatic process PVγ=C

1000.853=300VB53

VB=0.833/5=0.4 m3

Work done in an adiabatic process is given by,

W=P1V1-P2V2γ-1

WAB=PAVA-PBVB53-1=80-300×0.42/3 kJ

WAB=-60kJ

Therefore, option C is correct.

CA is isochoric D is correct.

For process BC

WBC=nRTlnV2V1=PVlnV2V1

WBC=300×0.4ln0.80.4

WBC=120×ln2 kJWBC=84 kJ

Therefore, option B is correct.

Now,

WAB+WBC=-60+84=24 kJ

Therefore, option A is incorrect.

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Asked in: JEE Advanced 2022 (Paper 2)

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