In the given figure, there is a circuit of potentiometer of length $A B = 10 m$ . The resistance per unit length is $0.1 Ω$ per $cm$ . Across $A B$ , a battery of emf $E$ and internal resistance $r$ is connected. The maximum value of emf measured by this potentiometer is:

Question

Aicharya · Accepted Answer

Maximum voltage that can be measured by this potentiometer will be equal to potential drop across $A B$ ,

$R_{AB} = 10 \times 0.1 \times 100 = 100 ohm$

$∴ V_{AB} = \frac{6}{20 + 100} \times 100 = 6 \times \frac{100}{120} = 5 V$

In the given figure, there is a circuit of potentiometer of length A B = 10   m . The resistance per…

Solution

In the given figure, there is a circuit of potentiometer of length A B = 10 &#160; m . The resistance per…

Solution

In the given figure, there is a circuit of potentiometer of length A B = 10 m . The resistance per…