In the given figure, the equivalent capacitance between points $A$ and $B$ is
In the given figure, the equivalent capacitance between points $A$ and $B$ is
$1.5 \mathrm{C}$
$2 \mathrm{C}$
$3 \mathrm{C}$
$6 \mathrm{C}$
Solution
Both parts have capacitors in parallel. The equivalent capacitor for each part is $\mathrm{C}_{\mathrm{eq}}=\mathrm{C}+\mathrm{C}+\mathrm{C}=3 \mathrm{C}$
There are two $3 \mathrm{C}$ capacitances in series
$\therefore \quad \frac{1}{\mathrm{C}_{\mathrm{AB}}}=\frac{1}{3 \mathrm{C}}+\frac{1}{3 \mathrm{C}}$
$\frac{1}{C_{A B}}=\frac{2}{3 C}$
$\therefore \quad \mathrm{C}_{\mathrm{AB}}=1.5 \mathrm{C}$
